1t^2+2t+8=0

Solution for 1t^2+2t+8=0 equation:

Simplifying
1t2 + 2t + 8 = 0

Reorder the terms:
8 + 2t + 1t2 = 0

Solving
8 + 2t + 1t2 = 0

Solving for variable 't'.

Begin completing the square.

Move the constant term to the right:

Add '-8' to each side of the equation.
8 + 2t + -8 + t2 = 0 + -8

Reorder the terms:
8 + -8 + 2t + t2 = 0 + -8

Combine like terms: 8 + -8 = 0
0 + 2t + t2 = 0 + -8
2t + t2 = 0 + -8

Combine like terms: 0 + -8 = -8
2t + t2 = -8

The t term is 2t.  Take half its coefficient (1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
2t + 1 + t2 = -8 + 1

Reorder the terms:
1 + 2t + t2 = -8 + 1

Combine like terms: -8 + 1 = -7
1 + 2t + t2 = -7

Factor a perfect square on the left side:
(t + 1)(t + 1) = -7

Can't calculate square root of the right side.

The solution to this equation could not be determined.